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 Depdendent Variable

 Number of equations to solve: 23456789
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 Dependent Variable

 Number of inequalities to solve: 23456789
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1. The equation is of the form a(x − h)^2 + k = 0
Corresponding parabola or quadratic function: y = a(x − h)^2 + k
Solutions are x-intercepts of this parabola  don’t forget ± sign

• Solutions are • Simplify and write as 2 separate numbers if − k/a is a perfect square

2. The equation is not in the above form.

• If the equation is not in the form ax^2 + bx + c = 0, then bring every term on one
side of “=”, foil (if necessary) and simplify to ax^2 + bx + c = 0
Corresponding parabola or quadratic function: y = ax^2 + bx + c
Solutions are x-intercepts of this parabola

• The solution is Simplify and write as 2 separate numbers if b^2 − 4ac is a perfect square

You will get:

 Discriminant Type of solution(* if p, q, r or a, b, c are integers) Graphically positiveperfect square not a perfect square 2 real solutions2 rational solution* 2 real solution with radicals conjugate to each other 2 x-intercepts parabola crosses x-axis twice zero 1 rational solution* only 1 x-intercept parabola just touches x axis negative 2 complex solutions conjugate to each other no x-intercept parabola does not intersect x axis

1. The function is in the form y = a(x − h)^2 + k
• Plot the points (h, k), (h + 1, k + a) and (h − 1, k + a)
• Draw the parabola through these points.

2. The function is in the form y = ax^2 + bx + c

• Plot the points:
y-intercept - (0, c), Point of symmetry (or
plug in x = − b/2a into y = ax^2 + bx + c to get y-coordinate of vertex)

• Draw the parabola through these points.

• a > 0 - parabola opens up (smilie) with minimum at the vertex
• a < 0 - parabola opens down (frownie) with maximum at the vertex

 y = a(x − h)^2 + k y = ax^2 + bx + c vertex (h, k) axis x = h symmetric points* (h + 1, k + a) and (h − 1, k + a) (0, c) and y-intercept (0, ah^2 + k) (0, c) x-intercept none if k > 0 if b^2 < 4ac one if k = 0 then (h, 0) if b^2 = 4ac then two if k < 0 then if b^2 > 4ac then * These points are on opposite sides of the axis, at equal distance from the axis and are at
the same height i.e. they have the same y-coordinate.

For horizontal parabola:

x = a(y − k)^2 + h - plot (h, k), (h + a, k + 1) and (h + a, k − 1) and draw the parabola
x = ay^2 + by + c - plot (c, 0), and draw the parabola
a > 0 - parabola opens right, a < 0 - parabola opens left